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Gravitational Force, Surface Gravity & Escape Velocity Calculator

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### Astrophysics & Orbital Mechanics: Newton's Law of Gravitation 1. **Inverse Square Law**: Gravitational attraction is proportional to the product of both masses and inversely proportional to the.

Reviewed by Ahmad Faraz · BSCS
Last updated:
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📊 Results

Gravitational Attraction & Orbital Summary
Gravitational Force: 1.9821e+20 N (4.4560e+19 lbf) ➔ Field Accel: 2.6975e-3 m/s² | Orbital Speed: 1.018 km/s (3,666 km/h) | Escape Speed: 1.440 km/s (3,221 mph)
Gravitational Attraction Force (F in Newtons [N] & lbf)
1.9821e+20 Newtons (4.4560e+19 lbf)
Gravitational Field Acceleration on m₂ (g in m / s²)
2.6975e-3 m / s² Gravitational Acceleration
Circular Orbital Velocity (v_orbit in km / s & km / h)
1.018 km / s (3,666 km / h Circular Orbit)
Parabolic Escape Velocity (v_esc in km / s & mph)
1.440 km / s (3,221 mph Escape Velocity)
Universal Gravitational Constant (G)
G = 6.67430 × 10⁻¹¹ N·m² / kg² (CODATA)
✦ Astrophysics & Orbital Mechanics Diagnostic
Newtonian Universal Gravitation Model (F = G·m₁m₂/r² | m₁ = 5.972e+24 kg | m₂ = 7.348e+22 kg | r = 384,400 km): [1. Gravitational Attraction]: The two celestial masses exert an attractive force of **1.9821e+20 Newtons (4.4560e+19 pounds-force)** upon each other. [2. Field Acceleration]: Primary mass m₁ creates a gravitational field acceleration of **g = 2.6975e-3 m/s²** at distance r. [3. Orbital Mechanics]: A secondary satellite in stable circular orbit requires an **Orbital Velocity of 1.018 km/s (3,666 km/h)**, and requires an **Escape Velocity of 1.440 km/s (3,221 mph)** to break free into parabolic interstellar trajectory.
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📐 Formula

Newton's Law of Universal Gravitation & Orbital equations:
Gravitational Attraction: F = G (m_1 m_2 ÷ r^2) (G = 6.67430 × 10^-11 N×m^2/kg^2)
Gravitational Acceleration: g = (G m_1 ÷ r^2) (m/s^2)
Circular Orbital Velocity: v_orbit = √((G m_1 ÷ r)) (m/s)
Escape Velocity: v_escape = √((2 G m_1 ÷ r)) = v_orbit × √(2)

💡 Practical Example

✅

For example, calculating the gravitational force between Earth) and the Moon) at an orbital distance of \}\): Gravitational Attraction Force is \(\mathbf{1.9820 \times 10^{20}\text{ Newtons (4.455 \times 10^{19} lbf)}}\). Lunar orbital velocity is \}\), with an escape velocity of \.

📖 About Gravitational Force, Surface Gravity & Escape Velocity Calculator

Astrophysics & Orbital Mechanics: Newton's Law of Gravitation

  • Inverse Square Law: Gravitational attraction is proportional to the product of both masses and inversely proportional to the square of the distance (doubling distance slashes gravitational pull by 75%).
  • The √(2) Escape Velocity Rule: A spacecraft in a circular orbit at speed v_orbit only needs to accelerate by a factor of √(2) ≈ 1.414 (a 41.4% speed increase) to attain escape velocity and permanently break orbit.

How to Use This Calculator

Enter your Astronomical System Preset — choose from Earth & Moon (m1=5.972e24 kg, m2=7.348e22 kg, r=384,400 km), Sun & Earth (m1=1.989e30 kg, m2=5.972e24 kg, r=1.496e8 km), Earth Surface & 70 kg Human (m1=5.972e24 kg, m2=70 kg, r=6,371 km), Primary Mass (m₁ [kg]) (e.g. 5.972e24 (Earth mass = 5.972 × 10²⁴ kg)), Secondary Mass (m₂ [kg]) (e.g. 7.348e22 (Moon mass = 7.348 × 10²² kg)), and Center-to-Center Distance (r [Kilometers - km]) (e.g. 384,400 (384,400 km Earth-Moon orbit)). Verify your units match the formula standard (SI vs imperial) before entering values.

The Formula

Newton's Law of Universal Gravitation \& Orbital equations:

Gravitational Attraction: F = G (m_1 m_2) / (r^2) (G = 6.67430 × 10^-11 N·m^2/kg^2)

Gravitational Acceleration: g = (G m_1) / (r^2) (m/s^2)

Circular Orbital Velocity: v_orbit = √((G m_1) / (r)) (m/s)

Escape Velocity: v_escape = √((2 G m_1) / (r)) = v_orbit × √(2)

Worked Example

For example, calculating the gravitational force between Earth) and the Moon) at an orbital distance of \: Gravitational Attraction Force is 1.9820 × 10^20 Newtons (4.455 × 10^19 lbf). Lunar orbital velocity is \, with an escape velocity of \.

Understanding Your Result

Force in Newtons (N): 1 N = 1 kg·m/s². Reference values: 1 kg object at Earth's surface weighs 9.81 N, atmospheric pressure 101,325 Pa (N/m²). Pressure benchmarks: car tire 30–35 psi (207–241 kPa), blood pressure systolic 120 mmHg (16 kPa), deep sea at 3,000m depth ~300 atm (30 MPa). Torque = Force × moment arm length — doubling the wrench length doubles the torque for the same applied force. Always verify whether gauge or absolute pressure is required for the application.

💡 Methodological Standards & Calculation Accuracy

  • All calculations are performed client-side in your browser using verified, standards-compliant mathematical algorithms.
  • Results are provided for educational and informational analysis; verify critical applications with certified domain specialists.
  • Ensure input values are entered in consistent units matching the selector options to guarantee accurate outputs.
  • Periodic recalibration is recommended whenever baseline assumptions, operating parameters, or external conditions change.

Results are for informational and educational purposes only. Always verify critical decisions with a qualified professional.

❓ Frequently Asked Questions

What is the formula for Newton's Law of Universal Gravitation?

F = G × ÷ r², where G is 6.67430 × 10⁻¹¹ N·m²/kg², m1 and m2 are masses in kg, and r is center-to-center distance in meters.

What is the escape velocity from Earth's surface?

Earth's surface escape velocity is approximately 11.186 km/s.

Why does gravity drop off by the square of distance?

Because gravitational field lines radiate outward uniformly in 3-dimensional space, spreading over the expanding surface area of a sphere.

How fast does the International Space Station (ISS) travel?

The ISS orbits at an altitude of ~400 km, requiring an orbital velocity of approximately 7.67 km/s (17,150 mph).

What is the value of the gravitational constant G?

The CODATA internationally recommended value for the Newtonian gravitational constant G is 6.67430 × 10⁻¹¹ N·m²/kg².

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