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Ohm's Law & Electrical Power (V, I, R, P

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### Physics & Electrical Engineering: The Four Fundamental Pillars of Ohm's Law Formulated by German physicist Georg Simon Ohm in 1827, **Ohm's Law** describes the proportional relationship between.

Reviewed by Ahmad Faraz · BSCS
Last updated:
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⚙ Input Values

📊 Results

Primary Ohm's Law & Power Summary
V = 120.00 V | I = 10.000 A | R = 12.000 Ω | P = 1200.00 W (1.200 kW)
Voltage (V in Volts)
120.000 Volts (V)
Current (I in Amperes / Amps)
10.0000 Amperes (A)
Resistance (R in Ohms Ω)
12.0000 Ohms (Ω)
Electrical Power (P in Watts & Kilowatts)
1200.00 Watts (1.200 kW)
Daily Energy Consumption (kWh / day)
4.800 kWh / day (4 hrs/day)
Monthly Electricity Operating Cost ($)
$23.36 / month (at $0.16/kWh)
✦ Circuit Theory & Electrical Safety Diagnostic
Electrical Circuit Analysis (Ohm's Law Wheel): At 120.00 Volts and 10.000 Amperes (Resistance: 12.000 Ω), the circuit dissipates 1200.00 Watts (1.200 kW) of electrical power. Operating for 4.0 hours/day consumes 4.800 kWh/day (146.0 kWh/month). At an electric utility rate of $0.160/kWh, operating cost is $0.77/day ($23.36/month). Circuit Safety: Draw of 10.00A requires at least a 15-Amp circuit (14 AWG wire).
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📐 Formula

Ohm's Law & Joule's Law of Electrical Power equations (The Ohm's Law Wheel): (Volts): V = I × R = (P ÷ I) = √(P × R) (Amps): I = (V ÷ R) = (P ÷ V) = √((P ÷ R)) (Ohms ): R = (V ÷ I) = (V^2 ÷ P) = (P ÷ I^2) Power (Watts): P = V × I = I^2 × R = (V^2 ÷ R) Consumption (kWh) = P_Watts × t_hours1,000

💡 Practical Example

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For example, analyzing a standard 120V household space heater drawing 10.0 Amps: \. Electrical Power is \}}\). Operating the heater 4.0 hours per day uses \, costing $0.77/day at $0.16/kWh.

📖 About Ohm's Law & Electrical Power (V, I, R, P

Physics & Electrical Engineering: The Four Fundamental Pillars of Ohm's Law

Formulated by German physicist Georg Simon Ohm in 1827, Ohm's Law describes the proportional relationship between electrical potential, flow of charge, and impedance in a DC or resistive AC circuit.

The 12 Formulas of the Ohm's Law Wheel

  • To find Voltage (V): I R, √(P R)
  • To find Current (I): \
  • To find Resistance (R): \
  • To find Power (P): V I, I^2 R, \

How to Use This Calculator

Enter your Select Any 2 Known Electrical Variables — choose from Voltage (V) and Current (I) -- Solve R & P, Voltage (V) and Resistance (R) -- Solve I & P, Current (I) and Resistance (R) -- Solve V & P, Voltage (V in Volts) (e.g. 120.0 (or 12V DC / 240V AC)), Current (I in Amperes / Amps) (e.g. 10.0), Resistance (R in Ohms Ω) (e.g. 12.0), Power (P in Watts) (e.g. 1200.0), Daily Operating Duration (Hours / Day) (e.g. 4.0 (for energy usage)), and Electricity Utility Rate ( / kWh) (e.g. 0.16). Verify your units match the formula standard (SI vs imperial) before entering values.

The Formula

Ohm's Law & Joule's Law of Electrical Power equations (The Ohm's Law Wheel): (Volts): V = I × R = (P) / (I) = √(P × R) (Amps): I = (V) / (R) = (P) / (V) = √((P) / (R)) (Ohms Ω): R = (V) / (I) = (V^2) / (P) = (P) / (I^2) Power (Watts): P = V × I = I^2 × R = (V^2) / (R) Consumption (kWh) = P_Watts × t_hours1,000

Worked Example

For example, analyzing a standard 120V household space heater drawing 10.0 Amps: . Electrical Power is . Operating the heater 4.0 hours per day uses costing 0.77/day at 0.16/kWh.

Understanding Your Result

Scientific calculations require careful attention to significant figures and units. Your result is only as precise as your least precise input — expressing the result with more significant figures than the inputs implies false precision. For laboratory or regulatory work, verify which measurement standard applies (SI, ASTM, ISO) and whether temperature, pressure, or concentration conditions affect the formula. Cross-reference results against published reference values for your specific material or compound.

💡 Methodological Standards & Calculation Accuracy

  • All calculations are performed client-side in your browser using verified, standards-compliant mathematical algorithms.
  • Results are provided for educational and informational analysis; verify critical applications with certified domain specialists.
  • Ensure input values are entered in consistent units matching the selector options to guarantee accurate outputs.
  • Periodic recalibration is recommended whenever baseline assumptions, operating parameters, or external conditions change.

Results are for informational and educational purposes only. Always verify critical decisions with a qualified professional.

❓ Frequently Asked Questions

What is Ohm's Law?

Ohm's Law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance: V = I × R.

How do you calculate power in watts from voltage and current?

Multiply voltage in volts by current in amperes: Power (Watts) = Voltage (Volts) × Current (Amperes), or P = V × I.

What happens to current if resistance doubles while voltage is constant?

Under Ohm's Law, doubling the resistance cuts the electrical current in half (inverse relationship).

How do you convert Watts to Kilowatt-hours (kWh)?

Multiply the device's wattage by the number of hours operated, then divide by 1,000: kWh = ÷ 1,000.

Does Ohm's Law apply to AC (Alternating Current) circuits?

Yes, for pure resistive AC circuits. For circuits with inductors and capacitors, resistance (R) is replaced with impedance (Z): V = I × Z.

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