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Projectile Motion, Ballistic Trajectory & Flight Range Calculator

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### Classical Mechanics: 2D Projectile Motion & Parabolic Flight In ideal Newtonian physics (neglecting air aerodynamic drag), projectile motion represents the classic superposition of two.

Reviewed by Sagar Sageer · Associate Engineer
Last updated:
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📊 Results

Trajectory Range, Peak Height & Flight Time Summary
Range: 196.58 m (644.9 ft) ➔ Max Height: 35.77 m | Flight Time: 5.33 s | Impact Velocity: 45.4 m/s (163.4 km/h)
Total Horizontal Range (R in meters & feet)
196.58 m (644.9 ft)
Maximum Apex Height (H_max in meters & feet)
35.77 m (117.3 ft)
Total Time of Flight (T_flight in seconds)
5.33 Seconds (Apex at 2.63s)
Terminal Impact Velocity (v_impact in m/s & km/h)
45.39 m/s (163.4 km/h | 101.5 mph)
Impact Angle with Ground (θ_impact in degrees)
-35.7° Below Horizontal
Trajectory Altitude at Target Distance x (y(x) in meters)
34.72 m (113.92 ft) at x = 80m
✦ Classical Kinematics & Parabolic Trajectory Diagnostic
Projectile Motion & Parabolic Ballistics (v₀ = 45 m/s @ 35°, y₀ = 1.8 m, g = 9.81 m/s²): [1. Kinematic Components]: Initial Horizontal Velocity **v_0x = 36.86 m/s** | Initial Vertical Velocity **v_0y = 25.81 m/s**. [2. Trajectory Profile]: Reaches a **Maximum Peak Altitude (Apex) of H_max = 35.77 meters (117.3 ft)** at t = 2.63 seconds. [3. Downrange Impact]: Total flight duration is **T_flight = 5.33 seconds**, achieving a **Total Horizontal Range of R = 196.58 meters (644.9 ft)**. [4. Terminal Impact Kinematics]: Lands on ground with a terminal speed of **45.39 m/s (163.4 km/h | 101.5 mph)** at an impact angle of **-35.7° below horizontal**. [5. Evaluated Target Coordinate]: Altitude at x = 80m is 34.72 m (113.92 ft) at x = 80m.
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📐 Formula

2D Projectile Motion & Parabolic Kinematics equations:
v_0x = v_0 , v_0y = v_0
Maximum Apex Height: H_ = y_0 + v_0y^22g
Total Time of Flight: T_flight = v_0y + √(v_0y)^2 + 2g y_0g
Total Horizontal Range: R = v_0x × T_flight = v_0 × T_flight
Trajectory Equation: y(x) = y_0 + x - (g x^2 ÷ 2 v_0^2 ^2 )
Impact Velocity: v_impact = √(v_0x)^2 + (v_0y - g T_flight)^2

💡 Practical Example

✅

For example, launching a projectile with initial velocity \ at an angle \ from an elevation \ under Earth gravity \: Velocity components are \ = \mathbf{36.86\text{ m/s}}\) and \ = \mathbf{25.81\text{ m/s}}\). Maximum peak altitude is \} = 1.8 + 33.97 = \mathbf{35.77\text{ meters (117.4 ft)}}\). Total flight time is \(1.8)}}{9.80665} = \frac{25.81 + 26.49}{9.80665} = \mathbf{5.33\text{ seconds}}\). Total horizontal range is \}}\) with a terminal impact speed of \}}\).

📖 About Projectile Motion, Ballistic Trajectory & Flight Range Calculator

Classical Mechanics: 2D Projectile Motion & Parabolic Flight

In ideal Newtonian physics (neglecting air aerodynamic drag), projectile motion represents the classic superposition of two independent, perpendicular motions:

  • Horizontal Kinematics (Zero Acceleration): With no horizontal forces acting, horizontal velocity remains constant throughout flight = v_0 θ).
  • Vertical Kinematics (Constant Gravitational Acceleration): Gravity acts downward with constant acceleration slowing upward velocity to zero at the trajectory apex (apogee) before accelerating the projectile downward.
  • Optimal Launch Angles:
  • Level Ground): Range is maximized at exactly \).
  • Elevated Launch (y_0 > 0): Launching from a cliff or shoulder height shifts the optimal angle slightly below 45^ (typically 42^ to 44^) to capitalize on extended downward flight time.

How to Use This Calculator

Enter your Initial Launch Velocity (v₀ in m/s) (e.g. 45 (45 m/s = 162 km/h / 100.7 mph)), Launch Angle (θ in Degrees above horizontal) (e.g. 35 (45° maximizes level ground range)), Initial Launch Elevation / Height (y₀ in meters) (e.g. 1.8 (Release height above ground)), Gravitational Acceleration (g in m/s²) (e.g. 9.80665 (Earth: 9.81, Moon: 1.62, Mars: 3.71)), and Target Downrange Distance to Check (x in meters [Optional]) (e.g. 80). Measure twice before entering dimensions — small measurement errors scale up significantly in material estimates.

The Formula

2D Projectile Motion \& Parabolic Kinematics equations:

v_0x = v_0 θ, v_0y = v_0 θ

Maximum Apex Height: H_ = y_0 + v_0y^22g

Total Time of Flight: T_flight = v_0y + √(v_0y)^2 + 2g y_0g

Total Horizontal Range: R = v_0x × T_flight = v_0 θ × T_flight

Trajectory Equation: y(x) = y_0 + x θ - (g x^2) / (2 v_0^2 ^2θ)

Impact Velocity: v_impact = √(v_0x)^2 + (v_0y - g T_flight)^2

Worked Example

For example, launching a projectile with initial velocity \ at an angle \ from an elevation \ under Earth gravity Velocity components are \ = 36.86 m/s and \ = 25.81 m/s. Maximum peak altitude is \ = 1.8 + 33.97 = 35.77 meters (117.4 ft). Total flight time is 1.8)9.80665 = (25.81 + 26.49) / (9.80665) = 5.33 seconds. Total horizontal range is \ with a terminal impact speed of .

Understanding Your Result

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💡 Methodological Standards & Calculation Accuracy

  • All calculations are performed client-side in your browser using verified, standards-compliant mathematical algorithms.
  • Results are provided for educational and informational analysis; verify critical applications with certified domain specialists.
  • Ensure input values are entered in consistent units matching the selector options to guarantee accurate outputs.
  • Periodic recalibration is recommended whenever baseline assumptions, operating parameters, or external conditions change.

Results are for informational and educational purposes only. Always verify critical decisions with a qualified professional.

❓ Frequently Asked Questions

What is the formula for the range of a projectile?

On level ground: Range =) ÷ g. With initial elevation (y0 > 0): Range = v0·cos(θ) × [v0·sin(θ) + √ + 2·g·y0)] ÷ g.

What angle gives the maximum range for a projectile?

For launches on level ground, 45° provides the absolute maximum range. For launches starting above ground level (y0 > 0), the optimal angle is slightly less than 45°.

Does projectile mass affect trajectory in a vacuum?

No. In the absence of air resistance, all objects accelerate downward at the exact same rate (g) regardless of their mass or size.

How do you calculate maximum height (apex)?

Maximum height is calculated as: H_max = y0 +² ÷.

Why is the trajectory of a projectile a parabola?

Because horizontal position varies linearly with time while vertical position varies quadratically with time, combining into the parabolic equation y(x) = ax - bx².

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